1.7 determine acceleration from the gradient of a velocity-time graph

I find it helps to remember 'rise over run', all this means is that in order to work out the acceleration all you need to do is do velocity / time.

In the example above...

The acceleration represented by the sloping line is 2m/s². This is because the object increases its velocity from 0m/s to 8m/s in 4s therefore its acceleration is 8 ÷ 4 = 2m/s^2.